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Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer. The temperature increase between noon and and 4 p.m. was twice the temperature increase between 8 a.m. and noon. What was the temperature at 4 p.m?

 Oct 25, 2018

Best Answer 

 #1
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Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer

So at noon it was -14˚F + 10˚F = -4˚F 

The temperature increase between noon and and 4 p.m. was twice the temperature increase between 8 a.m. and noon

So the temperature increase between noon and and 4 p.m is 10 so \(2 \times 10=20\)

Finally -4˚F + 20˚F = 16˚F   The temperature at 4 p.m!

 

Hope it helps! 

 Oct 25, 2018
 #1
avatar+316 
+3
Best Answer

Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer

So at noon it was -14˚F + 10˚F = -4˚F 

The temperature increase between noon and and 4 p.m. was twice the temperature increase between 8 a.m. and noon

So the temperature increase between noon and and 4 p.m is 10 so \(2 \times 10=20\)

Finally -4˚F + 20˚F = 16˚F   The temperature at 4 p.m!

 

Hope it helps! 

Dimitristhym Oct 25, 2018

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