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We can use Law of Sines for this.

$\frac{\sin A}{a} = \frac{\sin B}{b} \\ \frac{\sin A}{9} = \frac{\sin72}{38} \\ \sin A = (9)(\frac{\sin72}{38}) \\ A = \arcsin(\frac{9\sin72}{38}) \\ A \approx 13.018 \text{ degrees}$

(To the nearest tenth it's 13.0º )