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By accident, six burned-out bulbs have been mixed in with 26 good ones. Ken is replacing old bulbs in his house. If he selects two bulbs at random from the box of 32, what is the probability they both work?

 

A. P(Both work) =  325/512

B. P(Both work) =  325/496

C. P(Both work) =  169/256

D. P(Both work) =  169/248

 Mar 29, 2016
 #1
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P(both work)   =  26/32  x   25/31   =  13/16 x 25/31   =  325 / 496

 

B is correct

 

 

 

cool cool cool

 Mar 29, 2016
 #2
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B 59958852412529565555558552

 Mar 29, 2016

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