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Let \(V = (1,1,2),\) and let \(P\) be the point in the plane \(4x + y - 3z = 1\) closest to \(V.\) To find \(P\) let \(Q = (0,1,0),\) which lies in the plane \(4x + y - 3z = 1.\) Find \(\overrightarrow{PV}.\)

 Jun 20, 2020
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PV = sqrt(6).

 Jun 28, 2020

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