\(\sqrt{2x-5}=\sqrt{3x-12}\)
\(2x-5=3x-12\)
\(2x=3x-7\)
\(-x=-7\)
\(x=7\)
.sqrt(2*x-5)=sqrt(3*x-12)
Square both sides
2x - 5 = 3x - 12
Subtract 2x from both sides, add 12 to both sides
7 = x
\(\sqrt{2x-5}=\sqrt{3x-12}\)
\(2x-5=3x-12\)
\(2x=3x-7\)
\(-x=-7\)
\(x=7\)