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There are girls and boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.

 May 10, 2020
 #3
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How many girls and boys? I don't think I can solve the problem without this, since it's looking for the proportion.

 May 10, 2020
 #4
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25 combanations, so total is 3628800....... simplify \(\frac{25}{3628800}\)which equals \(\frac{1}{145152}\)

 May 10, 2020
edited by Guest  May 10, 2020
 #5
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I'm afraid I don't understand. Are you the person who asked the question, and if yes, could you please inform me of how much of each gender? Thanks.

hugomimihu  May 10, 2020

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