There are girls and boys in a chess club. The club holds a round-robin tournament in which every player plays against every other player exactly once.

What fraction of the games are boy-versus-boy? Enter your answer as a fraction in simplified form.

Guest May 10, 2020

#3**+1 **

How many girls and boys? I don't think I can solve the problem without this, since it's looking for the proportion.

hugomimihu May 10, 2020

#4**0 **

25 combanations, so total is 3628800....... simplify \(\frac{25}{3628800}\)which equals \(\frac{1}{145152}\)

Guest May 10, 2020

edited by
Guest
May 10, 2020

#5**+1 **

I'm afraid I don't understand. Are you the person who asked the question, and if yes, could you please inform me of how much of each gender? Thanks.

hugomimihu
May 10, 2020