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here are the first five terms of an arithmetic sequence 2,7,12,17,22 explain why the number 271 cannot be a term in this sequence

 Oct 5, 2014

Best Answer 

 #1
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Each number in the sequence is obtained by adding 5 on to the previous number.  Since the sequence starts with 2 this means the numbers alternately end in 2 and 7.  271 doesn't end in 2 or 7 and hence is not included in the sequence.

 Oct 5, 2014
 #1
avatar+33616 
+5
Best Answer

Each number in the sequence is obtained by adding 5 on to the previous number.  Since the sequence starts with 2 this means the numbers alternately end in 2 and 7.  271 doesn't end in 2 or 7 and hence is not included in the sequence.

Alan Oct 5, 2014

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