+0  
 
0
722
3
avatar+23 
0.15 = 0.3 + x(0.33)
1-x


I hope this comes out right. the 0.3 + x(0.33) is all over 1-x
 Mar 30, 2014
 #1
avatar+118609 
0
ohnonotmath:

0.15 = 0.3 + x(0.33)
1-x


I hope this comes out right. the 0.3 + x(0.33) is all over 1-x



Hi ohnonotmath,
Your explanation of the question is good and leaves little room for misinterpretaion but I will show you how you could have presented this problem.

0.15 = (0.3 + x(0.33)) / (1-x)

0.15 = (0.3 + 0.33x) / (1-x)
At this point you need to recognise that you cannot divide by 0.
therefore 1-x cannot = 0 --> x cannot = 1
Now, multiply both sides by (1-x) to get rid of the fraction.

0.15(1-x) = 0.3 + 0.33x
Can you take over from here? I will check your final answer if you want me to.
 Mar 30, 2014
 #2
avatar+23 
0
Hello Melody!

0.15(1-x) = 0.3 + 0.33x
0.15 - 0.15x = 0.3 + 0.33x
(then I add 0.15x to both sides and subtract 0.3 from both sides)
0.15 - 0.3 = 0.15x + 0.33x
-0.15 = 0.48x
-0.15/0.48 = x
x = -0.312
?

Thanks for showing me how to set up the problem. Again it's one of those things I use to know but forgot over the years
 Mar 30, 2014
 #3
avatar+118609 
0
ohnonotmath:

Hello Melody!

0.15(1-x) = 0.3 + 0.33x
0.15 - 0.15x = 0.3 + 0.33x
(then I add 0.15x to both sides and subtract 0.3 from both sides)
0.15 - 0.3 = 0.15x + 0.33x
-0.15 = 0.48x
-0.15/0.48 = x
x = -0.3125 This is an exact answer, there is no need to round off.
?

Thanks for showing me how to set up the problem. Again it's one of those things I use to know but forgot over the years



So you are a mature aged student? What are you studying?
Have you collected your welcome message?
Melody
 Mar 30, 2014

2 Online Users