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avatar+43 

How can I factor this polynomial: k^2 - 17k + 16?

 Feb 9, 2017

Best Answer 

 #1
avatar+27001 
+15

(k-1)(k-16)

 Feb 9, 2017
 #1
avatar+27001 
+15
Best Answer

(k-1)(k-16)

ElectricPavlov Feb 9, 2017
 #2
avatar+101 
+11

\({k}^{2} -17k+16=0 \)

delta b²-4ac = (-17)²-4*1*16 = 225

\({k}_{1}= \frac{17+15}{2} = 16\)

\({k}_{2}=\frac{17-15}{2} = 1\)

\({k}^{2} -17k+16= (k-16)(k-1) \)

 Feb 9, 2017

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