How can I simplify....

thanks I understand now  but why couldn't the ^4 be made into ^3 too ?

sqrt(32) can be written as sqrt(16)*sqrt(2)

sqrt(16)=4

Therefore we got 4*sqrt(2)

Good luck!!

Thanks I figured this one out :)

I'm trouble understanding this one :/

√24 x^6 y^9 (Everything is under the square root sign)

The answer given was 2x^3 y^4 √6y  But I don't understand how the 3 and 4 was found

(a^x)^y=a^xy

sqrt(x)=x^1/2

so you can write your number like this: (24x^6y^9)^0,5

I hope you get it, I don´t now how else to explain it :/

The calculation:

sqrt(4*x^6*y^8)*sqrt(6y)

(4x^6y^8)^0,5*sqrt(6y)

sqrt(4)*x^(6*0,5)*y^(8*0,5)*sqrt(6y)=2*x^3*y^4*sqrt(6y)

:)))

Thanks! But I still don't understand 

Oh sorry, got a go now, but please tell me what the tricky part is so can I help later.

Okay I think I got it for the 3, so the ^9 is 9 * 0.5 = 4.5 and I just round it to 4 ??

No, just "Break out" (or whatever its called in english) y^8:s. the last y^1 is in the root with a 6.

sqrt(4*x^6*y^8)*sqrt(6y)

(4x^6y^8)^0,5*sqrt(6y)

sqrt(4)*x^(6*0,5)*y^(8*0,5)*sqrt(6y)=2*x^3*y^4*sqrt(6y)

 there you got all Y:s with exponents.

Try to follow the calculation backwards

I still don't get it :/ sorry

Thanks Headingnorth for that sterling effort.   

annon - I am pleased that you have persisted, that is a good thing, but do make sure you give yourself a little time to try and understand what you are being taught.

I shall try to help.    

√24 x^6 y^9 (Everything is under the square root sign)

The answer given was 2x^3 y^4 √6y  But I don't understand how the 3 and 4 was found

$$\\\sqrt{24*x^6*y^9}\\\\
=\sqrt{4*6}*\sqrt{x^3*x^3}*\sqrt{y^4*y^4*y}\\\\
=\sqrt{4}*\sqrt{6}*\sqrt{x^3*x^3}*\sqrt{y^4*y^4}*\sqrt{y}\\\\
=\sqrt{4}*\sqrt{x^3*x^3}*\sqrt{y^4*y^4}*\sqrt{6}*\sqrt{y}\\\\
=2*x^3*y^4*\sqrt{6y}\\\\
=2x^3y^4\sqrt{6y}\\$$

I am sorry but I do not understand the question. 

I gave you thumbs up for asking - I like everyone to ask questions.  I just don't understand  what you mean.