How can I solve for sec 100° 0' 5" ?

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How can I solve for sec 100° 0' 5" ?

Guest Jan 16, 2015

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Best Answer

+118723

+5

sec(100+5/360)

$${sec}{\left({\mathtt{100}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{360}}}}\right)} = -{\mathtt{5.750\: \!864\: \!607\: \!877\: \!902\: \!7}}$$

Melody Jan 16, 2015

2⁺⁰ Answers

+23254

+5

sec(100° 0' 5") = 1 / cos(100° 0' 5")

geno3141 Jan 16, 2015

+118723

+5

Best Answer

sec(100+5/360)

$${sec}{\left({\mathtt{100}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{360}}}}\right)} = -{\mathtt{5.750\: \!864\: \!607\: \!877\: \!902\: \!7}}$$

Melody Jan 16, 2015

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