This is the problem. e=2.71828
reliability(t)= e-(1/4000)(10/60
= e-(1/24000)
= 0.9999584
now according to the problem description the 4000 is the hours and the 10 is minutes. So the first part of the equation is solved like this 4000/1=4000 and 60/10=6 then you do 4000*6 to get 24000 which would make it turn into (1/24000). So I do understand how they got that number what I don't understand is how e-(1/24000) makes 0.9999584. Does anyone know how they got this number?
+33665 e is the number
$${\mathtt{e}} = {\mathtt{2.718\: \!281\: \!828\: \!459\: \!045\: \!2}}$$ ... except that it goes on forever.
If you raise this number to the power of -1/24000 you get:
$${{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{24\,000}}}}\right)} = {\mathtt{0.999\: \!958\: \!334\: \!201\: \!376\: \!8}}$$ ... which also goes on forever!
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+33665 e is the number
$${\mathtt{e}} = {\mathtt{2.718\: \!281\: \!828\: \!459\: \!045\: \!2}}$$ ... except that it goes on forever.
If you raise this number to the power of -1/24000 you get:
$${{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{24\,000}}}}\right)} = {\mathtt{0.999\: \!958\: \!334\: \!201\: \!376\: \!8}}$$ ... which also goes on forever!
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