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solve for the zeros by completing the square: f(x)= 2x^2-8x-22

 Dec 12, 2015
 #1
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Write it as 

 

2(x^2 - 4x - 11) = 0   Divide by 2

 

x^2 - 4x - 11 = 0   Add 4 to both sides (the square of half of the coefficient of x).

 

x^2 - 4x + 4 - 11 = 4   Add 11 to both sides

 

x^2 - 4x + 4 = 15   The left=hand side can now be written as a square:

 

(x - 2)^2 = 15  Take square root of both sides

 

\(x-2=\pm \sqrt{15}\)   Add 2 to both sides

 

\(x =2\pm \sqrt{15}\)

 Dec 12, 2015
edited by Alan  Dec 12, 2015

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