+0  
 
0
601
1
avatar

how do i figure out what # X is, in the equation x2-x+30=0?

 Mar 14, 2016
 #1
avatar
0

Solve for x:
x^2-x+30 = 0

Subtract 30 from both sides:
x^2-x = -30

Add 1/4 to both sides:
x^2-x+1/4 = -119/4

Write the left hand side as a square:
(x-1/2)^2 = -119/4

Take the square root of both sides:
x-1/2 = (i sqrt(119))/2 or x-1/2 = 1/2 (-i) sqrt(119)

Add 1/2 to both sides:
x = 1/2+(i sqrt(119))/2 or x-1/2 = 1/2 (-i) sqrt(119)

Add 1/2 to both sides:
Answer: |  x = 1/2+(i sqrt(119))/2    or     x = 1/2-(i sqrt(119))/2

 Mar 14, 2016

0 Online Users