+5 How do I solve this equation: Mari is paddling a kayak downstream at 3.0 m/s. The river is flowing at 9.0 m/s. What is her velocity. I know that v=d/t but where are distance and time?
+37084 Don't overthink it ! LOL The velocities are just additive 3 + 6 = 9 m/s
Believe me .... I paddled 450 miles of the Yukon River in a canoe two years ago.....it was always GREAT to find a fast current !!!!!!!!
+118653 Mmm
I think that is 9+3=12m/s don't you Electric Pavlov??
That sounds like a fabulous canoe hike! How long did it take you? Were you in Canada or Alaska?
I suppose it was summer...... Sounds really interesting :)
+118653 If she were paddling UPSTREAM then the current would be faster than her paddling and she'd be going DOWNSTREAM at 9-3=6m/s
Now that would be a really useless way to use up energy!
+37084 Well....yah....i guess I 'underthunk' it...but I hope the message was received (I WAS UNDER the Yukon River for a while)....think I'll have another beer......HaHa
thanx Melody.... check your messages
+37084 Summertime.... we averaged 55 miles /day for 8 days .....paddling 10 - 12 hours a day....but we are fitness animals......and we had good weather.
+37084 Whitehorse to Dawson with a day of re-floating in Dawson....it was a blast!!!
