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How do u do system of equations? I have one problem and I can't deal with it? 

 

2x+3y+1=0

3x-y-4=0

 Jun 20, 2016
 #1
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Solve the following system:
{1+2 x+3 y = 0 |     (equation 1)
-4+3 x-y = 0 |     (equation 2)
Express the system in standard form:
{2 x+3 y = -1 |     (equation 1)
3 x-y = 4 |     (equation 2)
Swap equation 1 with equation 2:
{3 x-y = 4 |     (equation 1)
2 x+3 y = -1 |     (equation 2)
Subtract 2/3 × (equation 1) from equation 2:
{3 x-y = 4 |     (equation 1)
0 x+(11 y)/3 = (-11)/3 |     (equation 2)
Multiply equation 2 by 3/11:
{3 x-y = 4 |     (equation 1)
0 x+y = -1 |     (equation 2)
Add equation 2 to equation 1:
{3 x+0 y = 3 |     (equation 1)
0 x+y = -1 |     (equation 2)
Divide equation 1 by 3:
{x+0 y = 1 |     (equation 1)
0 x+y = -1 |     (equation 2)
Collect results:
Answer: | {x = 1                    y = -1

 Jun 20, 2016

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