how do you get ln from ln(x) on the other side of the equation when you want to solve for x
ex.) ln[A]= -7.5975 but you want to solve for [A]
In order to get the variable a by itself, you'll need to take the base of natural log (e) of both sides of the equation.
ln(a) = -7.5975
e^(ln(a)) = e^(-7.5975)
a = e^(-7.5975)
a = 0.0005
Or, in a more sophisticated-looking format:
$${ln}{\left({\mathtt{a}}\right)} = -{\mathtt{7.597\: \!5}} \Rightarrow {\mathtt{a}} = {{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{3\,039}}}{{\mathtt{400}}}}\right)} \Rightarrow {\mathtt{a}} = {\mathtt{0.000\: \!501\: \!704\: \!127\: \!239}}$$
In order to get the variable a by itself, you'll need to take the base of natural log (e) of both sides of the equation.
ln(a) = -7.5975
e^(ln(a)) = e^(-7.5975)
a = e^(-7.5975)
a = 0.0005
Or, in a more sophisticated-looking format:
$${ln}{\left({\mathtt{a}}\right)} = -{\mathtt{7.597\: \!5}} \Rightarrow {\mathtt{a}} = {{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{3\,039}}}{{\mathtt{400}}}}\right)} \Rightarrow {\mathtt{a}} = {\mathtt{0.000\: \!501\: \!704\: \!127\: \!239}}$$
