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How do you solve : 10^ -2 Sorry if that's confusing! Thanks!

 Nov 14, 2014

Best Answer 

 #2
avatar+23254 
+8

10^(-2)   =   1 / (10^2)   =   1 / 100

 Nov 14, 2014
 #1
avatar+1090 
+5

$${{\mathtt{10}}}^{-{\mathtt{2}}} = {\frac{{\mathtt{1}}}{{\mathtt{100}}}} = {\mathtt{0.01}}$$

That's because you have to 1/10 * 1/10. When you do negative exponents, you are multiplying the number's recipricols. And 1/10 * 1/10 is the recipricol of ten multiplied by itself two times!

 Nov 14, 2014
 #2
avatar+23254 
+8
Best Answer

10^(-2)   =   1 / (10^2)   =   1 / 100

geno3141 Nov 14, 2014
 #3
avatar+1090 
0

Is my explanation correct? Or is it a little off?

 Nov 14, 2014
 #4
avatar+130511 
0

Nope...just fine, Mathematician......

 

 Nov 14, 2014

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