how do you solve 3x=4y+10 & 4x=-3y+11 to find the point of intersection by elimination?

3x= 4y+10     multiply this equation through by 4 =   12x =  16y + 40   (1)

4x= -3y+11    multiply this equation through by -3  = -12x =   9y  - 33   (2)

Add equations (1)  and (2)

0 = 25y + 7   subtract 7 from both sides

-7  = 25 y     divide both sides by 25

-7/25  = y

And substituting this value for y into (1) to find x, we have

3x = 4(-7/25) + 10

3x = -28/25 + 250/25

3x = 222/25  divide both sides by 3

x = 222/75   = 74/25

So {x, y}   = { 74/25 ,  -7 / 25 }