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How do you solve problems with two inequalities? 

 Dec 16, 2014

Best Answer 

 #2
avatar+23252 
+5

If your problem looks like this:  3  <  2x + 6  < 18

Get the variable term alone in the center section by doing the same thing to all three parts.

First, get rid of the 6, by subtracting 6 from all three parts:

                  3 - 6  <  2x + 6 - 6  <  18 - 6

                        -3  <  2x  <  12

Now, divide all three parts by 2:

                     -3 ÷ 2  <  2x ÷ 2  <  12 ÷ 2

                        -1.5  <  x  <  6

 Dec 16, 2014
 #1
avatar+64 
+5

Umm...

Take this equation for ex: 1k-4<2k-4

1k-4<2k-6

1k-4+4<2k-6+4

1k<2k-2

1k+2<2k-2+2

1k+2<2k

1k+2-1k<2k-1k

2<k

 

I hope this helped... sorry i couldn't go in depth

 Dec 16, 2014
 #2
avatar+23252 
+5
Best Answer

If your problem looks like this:  3  <  2x + 6  < 18

Get the variable term alone in the center section by doing the same thing to all three parts.

First, get rid of the 6, by subtracting 6 from all three parts:

                  3 - 6  <  2x + 6 - 6  <  18 - 6

                        -3  <  2x  <  12

Now, divide all three parts by 2:

                     -3 ÷ 2  <  2x ÷ 2  <  12 ÷ 2

                        -1.5  <  x  <  6

geno3141 Dec 16, 2014

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