how do you solve( x to the second power minus 10) =(x to the second power minus 98)
If you mean
$$x^2-10=x^2-98$$
There is no solution, it's a false statement.
$$x^{2-10}=x^{2-98}$$
this can be written as:
$$x^{88}=1$$
There are two real solutions here, namely x = ±1
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