Judy had a number of raisins. After eating one, she gave half the remainder to her sister. After eating another raisin, she gave a third of what was left to her brother. Judy now had only six raisins left. How many raisins did she start with?
+37084 Another way
x = original # raisins she has
x-1 = after eating one
1/2 (x-1) = how many after giving half away
(1/2 (x-1))-1 = after she eats another one (WHO eats ONE raisin at a time??? LOL)
2/3 (1/2 (x-1))-1) = how many she has left after giving 1/3 away = 6
So: 2/3 (1/2 (x-1))-1) = 6 Solve for 'x' x = 21
Judy had a number of raisins. After eating one, she gave half the remainder to her sister. After eating another raisin, she gave a third of what was left to her brother. Judy now had only six raisins left. How many raisins did she start with?
Since Judy has 6 raisins Left.
6 + 3 =9 what she had left before giving 1/3 to her brother.
9+1 =10 Number befor eating one and before giving 1/3 to her brother
10 x 2 =20 Number of raisins before she gave half to her sister.
20+1 =21 Number of raisins she started with.
There are many ways of solving this problems. This is the most childish and simplest!!!!!.
+37084 Another way
x = original # raisins she has
x-1 = after eating one
1/2 (x-1) = how many after giving half away
(1/2 (x-1))-1 = after she eats another one (WHO eats ONE raisin at a time??? LOL)
2/3 (1/2 (x-1))-1) = how many she has left after giving 1/3 away = 6
So: 2/3 (1/2 (x-1))-1) = 6 Solve for 'x' x = 21
ElectricPavlov:
I think you made a small mistake in your last equation, which gives the value of x=22!!.
+37084 Hmmmm.....No, it comes out to 21 when I worked it out again. Here are the steps:
2/3 (1/2 (x-1))-1) = 6
2/3 (1/2x -1/2 -1) = 6
2/3 (1/2x - 3/2)
2/6x - 1 = 6
1/3 x = 7
x = 21
