How many ways are there to put 5 b***s in 3 boxes if the b***s are not distinguishable and neither are the boxes?
You can put the first ball in any of 3 boxes, the second ball in any of 3 boxes, etc.
There are 3 choices for each ball, so there are 3x3x3x3x3 = 35 choices = 243 choices.
-----------------------------------------------------------------------------------------------------------------
.