+0  
 
0
484
0
avatar

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)How to do cheekymy math ia????frown :OOOO   \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 
 Dec 2, 2015

0 Online Users