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How to solve: 5x^2 = 4x -2 by completing the square?

 May 6, 2014
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Completing the square is very easy once you get the pattern down for it. You always want the x quanity and the x^2 quantity on the same side of the equation and you want the plain number quanity on the other side. You also want the x^2 quantity to have a coefficient of 1. 

 

In this case we have to divide by 5 first. And then we move the move the 4/5x over to the other side of the equation in order to set up properly: 

x^2 - 4/5x = -2/5 

 

Now that we have set up, we go about solving by completing the square. First you want to take half the coefficient of the term with the x on it and square it. In this case, take the -4/5 from (-4/5x), and divide it in half to get -2/5 and then square it to get 4/25. You then add this number to both sides of the equation: 

x^2 - 4/5x + 4/25 = -2/5 + 4/25.  

x^2 - 4/5x + 4/25 = -6/25 

 

You then examine the left side of the equation. It can now be factored in the form x + half the coeffeicent of the x term, squared, like so:  

(x + -2/5) ^ 2. 

Finally, you take the square root of both sides and you get: 

x - 2/5 = +- $${\frac{{\sqrt{{\mathtt{6}}}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{i}$$

x =   2/5 +- $${\frac{{\sqrt{{\mathtt{6}}}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{i}$$

 May 6, 2014

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