How would someone go about solving this?

Find the solutions of the following system. Then graph the system of equations to confirm your algebraic solutions.

2x-y=-3

4(x-2)+(y-1)=36

$\begin{array}{rcll} (1) & 2x-y&=&-3 \qquad & | \qquad \cdot (-1)\\ & -2x+y &=& 3 \qquad & | \qquad +2x\\ & y &=& 3 +2x\\\\ (2) & 4(x-2)+(y-1) &=& 36 \\ & 4x-8+y-1 &=& 36 \\ & 4x+y-9 &=& 36 \\ & 4x+y-9 &=& 36 \qquad & | \qquad +9\\ & 4x+y &=& 36+9\\ & 4x+y &=& 45 \qquad & | \qquad -4x\\ & y &=& 45-4x\\\\ x: & 3 +2x&=& 45-4x \qquad & | \qquad +4x\\ & 3 +6x&=& 45\qquad & | \qquad -3\\ & 6x&=& 42 \qquad & | \qquad :6\\ & \mathbf{ x }& \mathbf{=} & \mathbf{7}\\\\ y: & y &=& 3 +2x \qquad & | \qquad x=7\\ & y &=& 3 +2\cdot 7\\ & y &=& 3 +14\\ & \mathbf{y} &\mathbf{=}& \mathbf{17} \end{array}$