4x^2+8x+3=0
As an answer I got x=-4(plus or minus)square root of 13
all of the above (except for x) over 4
Is it correct or not?
Thank you, I always get great answers.
4x² + 8x + 3 = 0
First, move the number term to the other side:
Subtract 3 from both sides 4x² + 8x = -3
Then, divide both sides by the coefficient of the squared term:
Divide all the terms by 4: x² + 2x = -3/4
Now, three steps: divide the coefficient of the linear terms by 2: 2/2 = 1
square this result: 1² = 1
add this number to both sides of the equation:
x² + 2x + 1 = -3/4 + 1
Factor the left-hand side; simplify the right side:
(x + 1)² = 1/4
Find the square root of both sides: x + 1 = ± 1/2
Subtract 1 from both sides: x = -1 ± 1/2 ---> x = -1.5 or x = 0.5
4x² + 8x + 3 = 0
First, move the number term to the other side:
Subtract 3 from both sides 4x² + 8x = -3
Then, divide both sides by the coefficient of the squared term:
Divide all the terms by 4: x² + 2x = -3/4
Now, three steps: divide the coefficient of the linear terms by 2: 2/2 = 1
square this result: 1² = 1
add this number to both sides of the equation:
x² + 2x + 1 = -3/4 + 1
Factor the left-hand side; simplify the right side:
(x + 1)² = 1/4
Find the square root of both sides: x + 1 = ± 1/2
Subtract 1 from both sides: x = -1 ± 1/2 ---> x = -1.5 or x = 0.5