I am trying to express the radical in simplest form with a rationalized denominators. √(x^3 y^4 z^6 )

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Guest Feb 28, 2015

+33661

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Best Answer

$$\sqrt{x^3y^4z^6}=\sqrt{x\times x^2\times (y^2)^2\times (z^3)^2}=xy^2z^3\sqrt{x}$$

Note: There aren't any denominators!

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Alan Feb 28, 2015

Alan · Answer 1 · 2015-02-28T08:03:10

$$\sqrt{x^3y^4z^6}=\sqrt{x\times x^2\times (y^2)^2\times (z^3)^2}=xy^2z^3\sqrt{x}$$

Note: There aren't any denominators!

.