i need math help

I do not know if you want to solve for y or solve for x so I will do both.

 

Solve for x:

 

\(3+6x=11-4y\)

 

\(6x=8-4y\)

 

\(x=\frac{8-4y}{6}\)

 

Solve for y:

 

\(3+6x=11-4y\)

 

\(-8+6x=-4y\)

 

\(\frac{-8+6x}{-4}=y\)

 

\(y=\frac{-8+6x}{-4}\)\(\)