a) 3√b = b^(1/3) ....so we have
b^(1/3) / b^(1/6) ....remember a^m / a^n = a^(m-n)...so we have b^(1/3 - 1/6) = b^(1/6)
b) (x^3)^2 * y^(-2) / xy = x^6 / [x y^2 *y] = x^5 / y^3 .....remember a^(-n) = 1 / a^(n)....also (a^m)^n = a^(m x n)
c) a^3 x b^4 x a ^4 x a^3 = a^10 x b^4 ... the rule is a^n * a^m = a^(n+m)