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# I really need help on this

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If $$f(c)=\frac{3}{2c-3}$$, find $$\frac{kn^2}{lm}$$ when $$f^{-1}(c)\times c \times f(c)$$ equals the simplified fraction $$\frac{kc+l}{mc+n}$$\$, where $$k,l,m,\text{ and }n$$ are integers.

Jul 22, 2020

#1
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$$\frac{kn^2}{lm} = 8$$

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Jul 23, 2020
#2
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Jul 23, 2020