If \(f(c)=\frac{3}{2c-3}\), find \(\frac{kn^2}{lm}\) when \(f^{-1}(c)\times c \times f(c)\) equals the simplified fraction \(\frac{kc+l}{mc+n}\)$, where \(k,l,m,\text{ and }n\) are integers.
\(\frac{kn^2}{lm} = 8\)
My answer see: https://web2.0calc.com/questions/help_6239#r3
+865 
