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If \(f(c)=\frac{3}{2c-3}\), find \(\frac{kn^2}{lm}\) when \(f^{-1}(c)\times c \times f(c)\) equals the simplified fraction \(\frac{kc+l}{mc+n}\)$, where \(k,l,m,\text{ and }n\) are integers.

 Jul 22, 2020
 #1
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\(\frac{kn^2}{lm} = 8\)

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 Jul 23, 2020
 #2
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+1
 Jul 23, 2020

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