i really need some help answering this pls help, math related

$-\frac{2}{5}x-9<\frac{9}{10}$

First, add 9 to both sides.

$-\frac{2}{5}x<\frac{9}{10}+9$

Simplify

$-\frac{2}{5}x<\frac{99}{10}$

Divide both sides by -2/5

$x<\frac{\frac{99}{10}}{-\frac{2}{5}}$

Anything divided by a fraction is the same as that number multiplied by the fraction's reciprocal.

$x<\frac{99}{10}*-\frac{5}{2}$

99*-5=-495

10*2=20

$x<\frac{-495}{20}$

Reduce.

$\frac{-495}{20}=\frac{-99}{4}$

That is the furthest it can simplify, so x>-99/4. If you want that in decimal form, here it is.

$\frac{-99}{4}=-24.75$

-2/5x-9 < 9/10    add 9 to both sides

-2/5x < 9+9/10

-2/5x < 99/10     Multiply both sides by - 5/2 and reverse the inequality sign:

x > 99/10 x - 5/2

x > - 495 / 20     Reduce the RHS by dividing by 5

x > - 99 /4