If cosx=-5/13 determine tanx
This is a Pythagorean "Triple" .......
y = ±√[13^2 - (-5)^2] = ± 12
So.....the tanΘ = y/ x and so we have
tan Θ = ± 12 / 5
cos(x)=-5/13
cos(x)= adjacent/hyp
pitagoras:
-5^2+x^2=13^2
x=13.93----> opposite leg of the triangle
tan(x)=opposite leg/adjacent leg
tan(x)=13.93/-5