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If cosx=-5/13 determine tanx

 May 10, 2015

Best Answer 

 #2
avatar+130511 
+5

This is a Pythagorean "Triple"  .......

y = ±√[13^2 - (-5)^2]  = ±  12

So.....the tanΘ = y/ x     and so we have

tan Θ  =  ±  12 / 5

 

  

 May 11, 2015
 #1
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cos(x)=-5/13

cos(x)= adjacent/hyp

  pitagoras:

-5^2+x^2=13^2

x=13.93----> opposite leg of the triangle

tan(x)=opposite leg/adjacent leg

tan(x)=13.93/-5

 May 10, 2015
 #2
avatar+130511 
+5
Best Answer

This is a Pythagorean "Triple"  .......

y = ±√[13^2 - (-5)^2]  = ±  12

So.....the tanΘ = y/ x     and so we have

tan Θ  =  ±  12 / 5

 

  

CPhill May 11, 2015

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