If θ is a first-quadrant angle in standard position with P(u, v) = (3, 4), evaluate tan 2θ

Question

0

2674

3

Guest Dec 4, 2014

+130511

+5

Best Answer

tanΘ = 4/3 ..... so......

tan2Θ = 2tanΘ / (1 - tan²Θ) = 2(4/3) / (1 -(4/3)²) = (8/3) / (1 - 16/9) = (8/3) / (-7/9) = (8/3) (-9/7) = -72/21 = -24/7

CPhill Dec 4, 2014

CPhill · Answer 1 · 2014-12-04T04:28:26

tanΘ = 4/3 ..... so......

tan2Θ = 2tanΘ / (1 - tan²Θ) = 2(4/3) / (1 -(4/3)²) = (8/3) / (1 - 16/9) = (8/3) / (-7/9) = (8/3) (-9/7) = -72/21 = -24/7

BrittanyJ · Answer 2 · 2014-12-04T04:39:42

good job, CPhill!

CPhill · Answer 3 · 2014-12-04T04:55:43

Uh, thanks, Brittany.......!!!