if x=3 and y=-2 find the value of -2x+3y-6=__???
-2(3)+3(-2)-6=
-6-6-6=
-12-6= -18
\(-2x+3y-6\); \(x=3\), \(y=-2\)
\(-2*3+3*(-2)-6\)
\(-6+3*(-2)-6\)
\(-6+-6-6\)
\(-6-6-6\)
\(-12-6\)
\(-18\)
+1904 
