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If you go a length 'l' in the -x direction of a linear function y=kx+m from a point (a,b), what's the coordinates of the point you end up in?

 Nov 28, 2016
edited by Guest  Nov 28, 2016
edited by Guest  Nov 28, 2016
edited by Guest  Nov 28, 2016
edited by Guest  Nov 28, 2016
 #1
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So you are given    b = ka +m     then move -l

                                     k(a-l) +m

                                      ka-kl  +m

                                      (ka + m) -kl        remember we were givien ka+m = b  (see above)

                                       b - kl        equals the new 'y'

the new points would be

 

x,y =  ( (a-l) , (b-kl) )

 Nov 28, 2016

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