In the equation x^2+10x+24=(x+a)(x+b), b is an iinteger. Find algebraically all possible values of b.
If you factor x2 + 10x + 24, you get (x + 6)(x + 4).
So either a = 6 and b = 4 or a = 4 and b = 6.
The possible values of b are 4 and 6.
