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Solve 3t - 5 < t - 2 <= -3t + 7 - t + 8.  Give your answer as an interval.

 Jun 7, 2022
 #1
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\(3t-5

 

Adding \(4t\) gives \(7t-5<5t-2\leq15\).

 

Solving \(7t-5<5t-2\) and \(5t-2\leq15\) gives \(t<1.5\) and \(t\leq3.4\), respectively.

 

Combining these then shows that \(t<1.5\), so therefore in interval notation the answer is \((-\infty,1.5)\).

 Jun 7, 2022
 #2
avatar+162 
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Something went wrong with my Latex on line one, it's supposed to read \(3t-5 .

RainbowSquirrel53  Jun 8, 2022

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