F(x) = 2x+3.. Find F(F^-1(-5))
We need to find the inverse......Let's write this as :
y = 2x + 3 get x by itself
y - 3 = 2x divide by 2 on both sides
[ y - 3 ] / 2 = x "exchange" x and y
[x - 3 ] / 2 = y and for y, we can write :
[x - 3 ] / 2 = F-1(x)
So F-1(-5) = [ - 5 - 3 ] / 2 = -8 / 2 = -4
And F (F-1(-5)) = F(-4) = 2(-4) + 3 = -5
Notice something odd......the result of this is that the F and F-1 seemingly "cancel" each other and we're just left with the -5 !!!!!
In actuality......the result of F-1(-5) would lead us back to the original value for "x" that we put into F - in this case, 4 - and this returns the " -5" when we evalate F(4)
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F(x) = 2x+3.. Find F(F^-1(-5))
We need to find the inverse......Let's write this as :
y = 2x + 3 get x by itself
y - 3 = 2x divide by 2 on both sides
[ y - 3 ] / 2 = x "exchange" x and y
[x - 3 ] / 2 = y and for y, we can write :
[x - 3 ] / 2 = F-1(x)
So F-1(-5) = [ - 5 - 3 ] / 2 = -8 / 2 = -4
And F (F-1(-5)) = F(-4) = 2(-4) + 3 = -5
Notice something odd......the result of this is that the F and F-1 seemingly "cancel" each other and we're just left with the -5 !!!!!
In actuality......the result of F-1(-5) would lead us back to the original value for "x" that we put into F - in this case, 4 - and this returns the " -5" when we evalate F(4)
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