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F(x) = 2x+3.. Find F(F^-1(-5))

 Oct 28, 2015

Best Answer 

 #1
avatar+130547 
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F(x) = 2x+3.. Find F(F^-1(-5))

 

We need to find the inverse......Let's write this as :

 

y = 2x + 3      get x by itself

 

y - 3 = 2x      divide by 2 on both sides

 

[ y - 3 ] / 2 =  x    "exchange" x and y

 

[x - 3 ] / 2 = y    and for y, we can write :

 

[x - 3 ]  / 2  = F-1(x)

 

So  F-1(-5)  =   [ - 5 - 3 ] / 2 =   -8 / 2  = -4

 

And F (F-1(-5))  = F(-4)  =  2(-4) + 3 = -5

 

Notice something odd......the result of this is that the F and F-1 seemingly "cancel" each other and we're just left with the -5  !!!!!

 

In actuality......the result of F-1(-5)   would lead us back to the original value for "x" that we put into F - in this case, 4 - and this returns the " -5"  when we evalate F(4)

 

 

cool cool cool

 Oct 28, 2015
edited by CPhill  Oct 28, 2015
edited by CPhill  Oct 28, 2015
edited by CPhill  Oct 29, 2015
 #1
avatar+130547 
+10
Best Answer

F(x) = 2x+3.. Find F(F^-1(-5))

 

We need to find the inverse......Let's write this as :

 

y = 2x + 3      get x by itself

 

y - 3 = 2x      divide by 2 on both sides

 

[ y - 3 ] / 2 =  x    "exchange" x and y

 

[x - 3 ] / 2 = y    and for y, we can write :

 

[x - 3 ]  / 2  = F-1(x)

 

So  F-1(-5)  =   [ - 5 - 3 ] / 2 =   -8 / 2  = -4

 

And F (F-1(-5))  = F(-4)  =  2(-4) + 3 = -5

 

Notice something odd......the result of this is that the F and F-1 seemingly "cancel" each other and we're just left with the -5  !!!!!

 

In actuality......the result of F-1(-5)   would lead us back to the original value for "x" that we put into F - in this case, 4 - and this returns the " -5"  when we evalate F(4)

 

 

cool cool cool

CPhill Oct 28, 2015
edited by CPhill  Oct 28, 2015
edited by CPhill  Oct 28, 2015
edited by CPhill  Oct 29, 2015

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