Let (x,y) be an ordered pair of real numbers that satisfies the equation \(x^2+y^2=14x+48y\). What is the minimum value of x?
Using my earlier answer....we had a circle with a center of (7, 24) and a radius of 25
So....the minimum x value is at the point ( 7 - 25 , 24) = (-18, 24)
So....the minimum x value is -18
Thanks, CPhill! You can also complete the square, riight?
Yep...you can complete the square and you will still get the same "circle" equation that I got on the other problem....
+816 
