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Let (x,y) be an ordered pair of real numbers that satisfies the equation \(x^2+y^2=14x+48y\). What is the minimum value of x?

mathtoo  Aug 25, 2018
 #1
avatar+88775 
+3

Using my earlier answer....we had  a circle  with a center  of   (7, 24)  and a radius of 25

 

So....the minimum x value  is at the point  ( 7 - 25 , 24)   = (-18, 24) 

 

So....the minimum x value is  -18

 

 

cool cool cool

CPhill  Aug 25, 2018
edited by CPhill  Aug 25, 2018
 #2
avatar+599 
+2

Thanks, CPhill! You can also complete the square, riight?

mathtoo  Aug 25, 2018
 #3
avatar+88775 
+2

Yep...you can complete the square and you will still get the same  "circle" equation that I got on the other problem....

 

 

 

cool cool cool

CPhill  Aug 25, 2018

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