4 and 1 over 4 minus 1 and 2 over 3
\(\frac{4+1}{4-1} +\frac{2}{3} \) = \(\frac{5}{3}+\frac{2}{3}= \frac{7}{3}=2\frac{1}{3} \)
The question might have meant 4+(1/4) - (1+(2/3))
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Thank you Alan!
\(4\frac{1}{4}-1\frac{2}{3} \) = \( \frac{17}{4}-\frac{5}{3} \) = \(\frac{17\times 3-5\times 4 }{4\times 3} \) = \(\frac{31}{12} =2\frac{7}{12}\)
asinus :- ) !
4 and 1 over 4 minus 1 and 2 over 3 is two and seven over twelve.
+14985 
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