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-lg (1/u)

don't understand this with the - log and how they come to the result lg(u) hope you can help me

 Oct 11, 2018
 #1
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In general lg(ua) = a*lg(u).  When a is -1 then lg(u-1) = -1*lg(u)  or  lg(1/u) = -lg(u)

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 Oct 11, 2018

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