If the distance between (3, -2) and (4, a) is the sqaure root of 7, find the exact value of a.
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\(\sqrt{(4-3)^2+(a--2)^2}=\sqrt7\\ (4-3)^2+(a--2)^2=7\\ 1+(a+2)^2=7\\ (a+2)^2=6\\ a+2=\pm\sqrt6\\ a=-2\pm\sqrt6\\ \)
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