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log with a base of two and exponent of eight plus log with a base of two and exponent of sixteen.

 Apr 3, 2015

Best Answer 

 #1
avatar+23254 
+5

Adding logs can be replaced by multiplying the numbers:

log28 + log216 =  log2(8·16)  =  log2(128)  =  log2(27)  =  7

or:  log28  =  3     and   log216  =  4      --->      log28 + log216 =  3 + 4  =  7

 Apr 3, 2015
 #1
avatar+23254 
+5
Best Answer

Adding logs can be replaced by multiplying the numbers:

log28 + log216 =  log2(8·16)  =  log2(128)  =  log2(27)  =  7

or:  log28  =  3     and   log216  =  4      --->      log28 + log216 =  3 + 4  =  7

geno3141 Apr 3, 2015

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