How do I evaluate this???
(2/3)^0+(3^-1)/2
Simplify the following: (2/3)^0+(1/2)/3
(2/3)^0 = 1: 1+1/(2×3)
2×3 = 6: 1+1/6
Put 1+1/6 over the common denominator 6. 1+1/6 = 6/6+1/6: 6/6+1/6
6/6+1/6 = (6+1)/6: (6+1)/6
6+1 = 7: Answer: | 7/6
