1/12 to the second power plus 12x =
\((\frac{1}{12}){}^{2}+12x\)
\(\frac{1}{12}\times\frac{1}{12}+12x\)
\(\frac{1}{144}+12x\)
\(12x+\frac{1}{144}\)
\(12x+0.006944444444...\)
(1/12)^2+12x=1728x-1/144
+1904 
