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R3 = sqrt(4hp) solve for P

 Mar 8, 2018
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\(R^3=\sqrt{4hp}\\ \text{Square both sides to remove square root}\\ (R^3)^2=(\sqrt{4hp})^2\\ R^6=4hp\\ \text{Divide 4h to isolate p}\\ \frac{R^6}{4h}=p \)

 

For line 3, one of the law of exponents state:
\((x^a)^b=x^{ab}\)

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 Mar 8, 2018

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