We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
235
1
avatar

R3 = sqrt(4hp) solve for P

 Mar 8, 2018
 #1
avatar+118 
0

\(R^3=\sqrt{4hp}\\ \text{Square both sides to remove square root}\\ (R^3)^2=(\sqrt{4hp})^2\\ R^6=4hp\\ \text{Divide 4h to isolate p}\\ \frac{R^6}{4h}=p \)

 

For line 3, one of the law of exponents state:
\((x^a)^b=x^{ab}\)

.
 Mar 8, 2018

17 Online Users