math

.I think you can just transpose it to find the value for x. Therefore what you do to one side to change an individual identity (working with it's opposite to remove it) must be done to the other side. What sides? Each side of the equals, the left hand side and right hand side. Hope this helps. The answer is x is equal to 5/4 try to get to that.
____________
Thanks

Stu,
Learning E&E

Here is an explaination.
http://www.mathportal.org/algebra/solving-equations/solving-linear-equations.php
Good luck, post in this thread again if stuck.

Stu,

I'm pretty sure the answer is not 5/4. If you plug in 5/4 for x, you'll see that it doesn't work. I'm not sure what you did wrong, but the answer is 5/2. Everything else you said in order to solve it is good, though. I would remind you that when you try to get an x ² to just x by square rooting both sides of the equation, you must make sure to sqrt. both the numerator and denominator if you have a fraction on the other side. I.e. 25/4 = Sqrt(25)/Sqrt.(4).

Just remember, Logan, that the easiest way to solve these simple algebraic equations is to get everything with x attached to it on one side, and everything without x attached to it on the other side. From there, it's just simplifying and simple algebra. Best of luck!

Hope that helps!

Warm Regards,
Grammar Fascist

Thanks, yes I knew in my mind the whole fraction was rooted, could see it didnt look right, but skipped a step and - proof Im still learning. Sorry op for mistake. Thought I had this down pat.

Stu,

You're all good, man. Just had to get you back. ;P I think we're all still learning...perhaps save Rom. Haha!

Warm Regards,
Grammar Fascist