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# math

+1
215
1

2/3k>6

Guest May 9, 2017
#1
+7155
+2

If you want to solve for k:

$$\frac23k>6$$

Multiply both sides of the equation by $$\frac32$$ .

$$k>6*\frac32 \\~\\ k>9$$

hectictar  May 9, 2017