A baseball diamond is a square with sides of 80 feet. What is the shortest distance, to the nearest tenth of a foot, between first base and third base?
The diagonal of any square = S*sqrt(2) where S is the side length of the square
So 80* sqrt(2) = about 113.14 ft
A straight line from 1st. base to 3rd.base=113.137 Feet
80^2 + 80^2=12,800
Sqrt(12,800)=113.137
